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while y[i]==y[-1-i]: i=i+1 if i>=(n//2): #since i must go till n//2-1 break #will break out of the while loop altogether if i==(n//2): #after full iteration from i=0 to the (n//2-1)th element, i+1 ...

The previous solution which contains a while loop is actually quite slow. The example solution could be optimized to be a modified version of the integer reverse digits solution that executes in O(1).